Leetcode 026 Remove Duplicates from Sorted Array

Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same.

Since it is impossible to change the length of the array in some languages, you must instead have the result be placed in the first part of the array nums. More formally, if there are k elements after removing the duplicates, then the first k elements of nums should hold the final result. It does not matter what you leave beyond the first k elements.

Return k after placing the final result in the first k slots of nums.

Do not allocate extra space for another array. You must do this by modifying the input array in-place with O(1) extra memory.

Custom Judge:

The judge will test your solution with the following code:

int[] nums = […]; // Input array int[] expectedNums = […]; // The expected answer with correct length

int k = removeDuplicates(nums); // Calls your implementation

assert k == expectedNums.length; for (int i = 0; i < k; i++) { assert nums[i] == expectedNums[i]; } If all assertions pass, then your solution will be accepted.

Input: nums = [1,1,2]
Output: 2, nums = [1,2,_]
Explanation: Your function should return k = 2, with the first two elements of nums being 1 and 2 respectively.
It does not matter what you leave beyond the returned k (hence they are underscores).

Input: nums = [0,0,1,1,1,2,2,3,3,4]
Output: 5, nums = [0,1,2,3,4,_,_,_,_,_]
Explanation: Your function should return k = 5, with the first five elements of nums being 0, 1, 2, 3, and 4 respectively.
It does not matter what you leave beyond the returned k (hence they are underscores).

• Soruda bize bir array veriliyor.Bu array içerisinde soldan sağa artarak ilerleyen tekrar eden rakamlar var.Bizden istenen aynılarından sadece bir tane olacak şekilde array yeniden düzenlememiz isteniyor.
• Çözüm için iki işaretçi kullanabiliriz.Left ve right diye iki işaretçimiz olsun.
• İkisini de 1. indeksten başlatırız. Çünkü 0. indeksteki rakam hep orada kalacak.
• Daha sonra right ilerletiriz ve right-1 indeks ile aynı mı diye kontrol ederiz.Aynı ise devam ederiz.
• Farklı ise right indeksteki sayıyı left indekse koyar ve left indeksi 1 arttırırız.

    def removeDuplicates(self, nums: List[int]) -> int:
        left = 1
        
        for right in range(1, len(nums)):
            if nums[right] != nums[right-1]:
                nums[left] = nums[right]
                left+=1
        return left