Leetcode 509 Fibonacci Number
The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,
F(0) = 0, F(1) = 1 F(n) = F(n - 1) + F(n - 2), for n > 1. Given n, calculate F(n).
Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.
Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.
- Fibonacci sorusunun çözümü isteniyor.
- Dinamik programlama ile çözebiliriz.
class Solution(object):
def fib(self, n: int) -> int:
if n<2: return n
dp = [0]*(n+1)
dp[1] = 1
for i in range(2,n+1):
dp[i] = dp[i-1]+dp[i-2]
return dp[n]